Which shows the correct substitution of the values a, b, and c from the equation 0 = 4x2 + 2x – 1 into the quadratic formula below? Quadratic formula: x =

Respuesta :

we know that

The quadratic formula is equal to

[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}}{2a}[/tex]

in this problem we have

[tex]4x^{2}+2x-1=0[/tex]

so

[tex]a=4\\b=2\\c=-1[/tex]

substitute the values in the formula

[tex]x=\frac{-2(+/-)\sqrt{2^{2}-4*(4)*(-1)}}{2*(4)}[/tex]

[tex]x=\frac{-2(+/-)\sqrt{4+16}}{8}[/tex]

[tex]x=\frac{-2(+/-)\sqrt{20}}{8}[/tex]


The correct substitution to the equation 4x² + 2x - 1 = 0 is  [tex]x=\frac{-2\pm\sqrt{2^2-4(4)(-1)} }{2(4)}[/tex]

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Given the quadratic equation:

ax² + bx + c = 0

The solution is at:

[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

Given the equation:

4x² + 2x - 1 = 0

a = 4, b = 2, c = -1

Hence:

[tex]x=\frac{-2\pm\sqrt{2^2-4(4)(-1)} }{2(4)}[/tex]

The correct substitution to the equation 4x² + 2x - 1 = 0 is  [tex]x=\frac{-2\pm\sqrt{2^2-4(4)(-1)} }{2(4)}[/tex]

Find out more on equation at: https://brainly.com/question/2972832