Respuesta :

[tex]3x^2 + 17x - 6 = 0\\ 3x^2-x+18x-6=0\\ x(3x-1)+6(3x-1)=0\\ (x+6)(3x-1)=0\\ x=-6 \vee x=\dfrac{1}{3}[/tex]

Answer:

x= -6

x= 1/3

Step-by-step explanation:

answer on edg