Respuesta :

pOH of a 0.0072 M=-lg(0.0072) = 2.1426675

Answer : 2.14

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

Given : [tex]NaOH\rightarrow Na^++OH^-[/tex]

1 mole of [tex]NaOH[/tex] gives 1 mole of [tex]OH^_[/tex]

Thus 0.0072 moles of  [tex]NaOH[/tex] will give= 0.0072 moles of [tex]OH^_[/tex]

[tex]pOH=-\log [OH^][/tex]

[tex]pOH=-\log (0.0072)[/tex]

[tex]pOH=2.14[/tex]

Therefore, the pOH of the basic solution is 2.14.