the answer
the table is
x 0 1 4 5 7
y 3 1 0 -2 -2
the approximate line of best fit to be y = –0.7x + 2.36
so when the value of x=5, the residual value is
y = –0.7(5) + 2.36 = -1.14 this is the actual value
the predicted value is -2 (for x=5)
and residual value formula is RS = y actual value - y predicted value
so RS = -1.14 - (-2) = 0.86
