At a game booth, a student gets a box of candy as the prize for winning a game. The boxes come in four colors: white, red, green, and blue. There are 6 boxes of each color. All the boxes are equally likely to be given away as prizes. Which expression shows the probability of the first winner receiving a white box and the second winner also receiving a box of the same color? A 6/24*6/23 B 6/24*5/23 C 6/24+5/23 D 6/24+6/23

Respuesta :

We know that the boxes come in four colors: white, red, green, and blue.
Also, there are 6 boxes of each color, which means that there are 6 white boxes, 6 red boxes, 6 green boxes, and 6 blue boxes.
So there are 24 boxes in total
Next step:
P(receiving a white box for the first pick):
6/24
Because there are 6 white boxes over the total amount of boxes to find the probability
Then,
After picking a first white boxes, now there are only 5 white boxes left without replacing, which lead to there are also 23 boxes in total left
P(receiving a white boxes in second pick):
5/23
As a result, the probability of the first winner receiving a white box and the second winner also receiving a box of the same color is 6/24×5/23=5/92, so the final answer will be B 6/24*5/23. Hope it help!

The probability of the first winner receiving a white box and the second winner also receiving a box of the same color is [tex]P=\dfrac{6}{24}\times \dfrac{5}{23}[/tex]. Option B is correct.

What is probability?

Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

Given that the boxes come in four colors: white, red, green, and blue. Also, there are 6 boxes of each color, which means that there are 6 white boxes, 6 red boxes, 6 green boxes, and 6 blue boxes.

There are 24 boxes in total. P(receiving a white box for the first pick):

6/24.

Because there are 6 white boxes over the total amount of boxes to find the probability.

Then, after picking the first white boxes, now there are only 5 white boxes left without replacement, which leads to there are also 23 boxes in total left

P(receiving a white box in the second pick): 5/23.

As a result, the probability of the first winner receiving a white box and the second winner also receiving a box of the same color is

6/24×5/23=5/92

Therefore, the probability of the first winner receiving a white box and the second winner also receiving a box of the same color is [tex]P=\dfrac{6}{24}\times \dfrac{5}{23}[/tex]. Option B is correct.

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