What is the equation, in slope-intercept form, of the line that is perpendicular to the line y – 4 = –2/3 (x – 6) and passes through the point (−2, −2)?
y-4=-2/3(x-6) (y-(-2))=(-3/2)(x-(-2)) (y+2)=(-3/2)(x+2) y-4=(-2/3)x+4 y=(-2/3)x+8 y+2=(-3/2)x-3 y=(-3/2)x-5 m2=(-3/2), (-2,-2) y=(-3/2)x+b (-2)=(-3/2)(-2)+b -2=-3+b 1=b d.) y=x+1, as the y-intercept is positive
