Answer:
Option B. is the correct option.
Step-by-step explanation:
Triangular base of the pyramid is an equilateral triangle. So, every angle of the triangle will be 60°
Length of the edge of this triangular base is S. In the figure attached we can see an equilateral triangle ABC with a side S and every angle = 60°
Now in ΔABC
tan60° = [tex]\frac{Height}{Base}[/tex]
√3 = [tex]\frac{AD}{\frac{S}{2}}[/tex]
AD = [tex]\sqrt{3}(\frac{S}{2})=\frac{S\sqrt{3}}{2}[/tex]
Therefore, Option B. [tex]\frac{S\sqrt{3}}{2}[/tex] is the correct option.
