Answer:
No solution.
The solution set is [tex]\left \{ \phi \right \}[/tex]
Step-by-step explanation:
We have been given the quadratic inequality [tex]6x^2+1\leq 0[/tex]
Subtract 1 to both sides
[tex]6x^2+1-1\le \:0-1\\\\6x^2\le \:-1[/tex]
Divide both sides by 6
[tex]\frac{6x^2}{6}\le \frac{-1}{6}\\\\x^2\le \:-\frac{1}{6}[/tex]
Now, we know that square of a number always gives positive values.
Thus, the above result never hold true for any real values of x.
Therefore, the inequality has no solution.
Hence, the solution set is [tex]\left \{ \phi \right \}[/tex]
