The x intercepts of the graph of the function f(x)=x^2+4x-12 are x = 2 and x = -6
How to determine the x-intercept
The function is given as:
f(x) = x^2 +4x - 12
Set the function to 0
x^2 +4x - 12 = 0
Expand the function
x^2 + 6x - 2x - 12 = 0
Factorize
x(x + 6) -2(x + 6) = 0
Factor out x + 6
(x -2)(x + 6) = 0
Split
x - 2 = 0 or x + 6 = 0
Solve for x
x = 2 or x = -6
Hence, the x intercepts of the graph of the function f(x)=x^2+4x-12 are x = 2 and x = -6
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