Respuesta :
The graph of the journey is shown in the speed-time graph below
At the time = 3 minutes, Peter would have achieved the speed V.
The distance he travelled is the area under the line as shown in the graph
We first need to find the V by using the area of a rectangle formula
[tex]Area= \frac{(b)(h)}{2} [/tex]
[tex]330= \frac{3h}{2} [/tex]
[tex]660=3h[/tex]
[tex]h=660/3=220[/tex]
so V=220
the gradient the f slope then given as [tex] \frac{220}{3} [/tex]
At the time = 3 minutes, Peter would have achieved the speed V.
The distance he travelled is the area under the line as shown in the graph
We first need to find the V by using the area of a rectangle formula
[tex]Area= \frac{(b)(h)}{2} [/tex]
[tex]330= \frac{3h}{2} [/tex]
[tex]660=3h[/tex]
[tex]h=660/3=220[/tex]
so V=220
the gradient the f slope then given as [tex] \frac{220}{3} [/tex]

Answer:
Slope = 110
Step-by-step explanation:
We have been given that Peter walks 3 minutes at a constant rate and travels 330 meters.
We know that slope of a line is known a s rise over run, so we can represent our given information as:
[tex]\text{Slope}=\frac{\text{Rise}}{\text{Run}}[/tex]
[tex]\text{Slope}=\frac{110\text{ meters}}{\text{ minute}}[/tex]
Therefore, the slope of the line representing this relationship is 110.