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Anya found the slope of the line that passes through the points (–7, 4) and (2, –3). Her work is shown below. Let (x2, y2) be (–7, 4) and (x1, y1) be (2, –3). m = = = The slope is . What error did she make? She simplified the denominator incorrectly. The denominator simplifies to –7. She labeled the points incorrectly. The point (–7, 4) should be (x1, y1). She used an incorrect formula. The formula should be the change in y-values with respect to the change in the x-values. She used an incorrect formula. The formula should be the sum of the x-values with respect to the sum of the y-values.

Respuesta :

Vtron
C.She used an incorrect formula. The formula should be the change in y-values with respect to the change in the x-values.

Answer:

The formula should be the change in y-values with respect to the change in the x-values.

Step-by-step explanation:

Given that slope of the line passing through two points was found as per working shown.

We are to locate the error in the method

Slope of the line passing through two points = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Here (x2, y2) be (–7, 4) and (x1, y1) be (2, –3).

Hence numerator = 4-(-3) =7

and denominator = -7-2=-9

The formula should be the change in y-values with respect to the change in the x-values.

If we use this formula only we get correct slope.

But Anya used formula incorrectly.

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