Answer:
Measurement of side b = 17.1
Step-by-step explanation:
In a given triangle ABC, it is given a = 18.2, ∠B = 62° and ∠C = 48° and we have to find the measurement of b.
Now by Sine Rule
[tex]\frac{sinB}{b}=\frac{sinA}{a}[/tex]
Here ∠C and ∠B are given so we can get the measurement of ∠A.
∠A + ∠B + ∠C = 180°
∠A + 62 + 48 = 180
∠A = 180 - 110 = 70°
Now we put these values in the sine rule.
[tex]\frac{sin62}{b}=\frac{sin70}{18.2}[/tex]
[tex]\frac{0.88}{b}=\frac{0.94}{18.2}[/tex]
[tex]b=\frac{(0.88)(18.2)}{0.94}=17.09[/tex]
Therefore measurement of side b will be 17.1
