Answer:
The x-intercepts of the quadratic function are -7 and 5.
Step-by-step explanation:
The given function is
[tex]f(x)=x^2+2x-35[/tex]
Equate f(x)=0, to find the x-intercepts of the function.
[tex]x^2+2x-35=0[/tex]
[tex]x^2+7x-5x-35=0[/tex]
[tex]x(x+7)-5(x+7)=0[/tex]
[tex](x+7)(x-5)=0[/tex]
[tex]x+7=0\Rightarrow x=-7[/tex]
[tex]x-5=0\Rightarrow x=5[/tex]
Therefore the x-intercepts of the quadratic function are -7 and 5.
