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if a lawn measures 40 and 4/5 ft by 50 and 7/8ft how many square feet of seed will he need?

Respuesta :

apologiabiology
so convert to improper fracitons (improper=x/y where x>y and the current one is mixed where it is in t s/f form) so

40 and 4/5=(40 times 5)/5 and 4/5=200/5 and 4/5=204/5

50 and 7/8=(50 times 8)/8 and 7/8=400/8 and 7/8=407/8

area=legnth times width
legnth =407/8
width=204/5
multiply 407/8 and 204/5

407/8 times 204/5=(407 times 204)/(8 times 5)=83028/40=2075.7 square feet

the answer is 2075.7 ft^2 of seed
thompzac
To solve this just take 40 4/5*50 7/8=2075.7 so there would be about 2075.7 square feet of seed to plant.

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