Answer:
The area of figure ABCD is:
24 square units.
Step-by-step explanation:
We see that the given points form the vertices of a trapezium ABCD with bases AD and CB with measure,
AD= 3 units
and CB=5 units
and the height of the trapezium is: AB= 6 units.
Hence, the area of trapezium ABCD is:
[tex]Area=\dfrac{1}{2}\times (AD+CB)\times AB\\\\\\Area=\dfrac{1}{2}\times (3+5)\times 6\\\\\\Area=\dfrac{1}{2}\times 8\times 6\\\\\\Area=24[/tex]
Hence, the area of figure ABCD is:
24 square units.
