The following illustration contains the stoichiometric quantities of the reactants for this reaction.
In the Haber process, nitrogen (N2) and hydrogen (H2) are directly combined to form ammonia (NH3). The reaction is as follows :
N[tex] N_{2} [/tex] + [tex]3 H_{2} [/tex] = [tex] 2NH_{3} [/tex]
Therefore, 1 mole of nitrogen is equivalent to 3 moles of Hydrogen
