Respuesta :

tonb
Let's present a solution for the generic case.
The equation will be of the form y=ax+b

If (7,3) is on it, then 3=7a+b
If (14,6) is on it, then 6=14a+b

Now we have a system we can solve.

3=7a+b => b = 3-7a
6=14a + 3-7a => 3 = 7a => a=3/7

b  = 3-7*3/7 = 0

So y = (3/7)x is the equation.

The equation of the line is y = (3/7)x.

What is the equation of a straight line?

The standard equation of a straight line is y =mx+c.

Here m is the slope and c is the y-intercept.

The line passes through the points

(7,3) (14,6) and (21,9)

The slope of the line is m = (y'-y)/(x'-x),

where (x,y) and (x',y') are two points on the line.

m = (6-3)/(14-7) = 3/7

y = (3/7)x + c

The line passes through the point ( 7,3)

3 = 3 +c

c =0

y = (3/7)x

= 7y = 3x

Therefore, the equation of the line is y = (3/7)x.

To know more about Equation of the straight line

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