Respuesta :
If the speed of the object becomes double, its kinetic energy changes to four times the initial kinetic energy. Hope it help!
Explanation:
The mathematical expression for the kinetic energy is given by :
[tex]E_k=\dfrac{1}{2}mv^2[/tex]
Where
m is the mass of the object
v is the velocity with which the object is moving
According to given condition, if the speed of an object doubles, v' = 2v. So, kinetic energy becomes :
[tex]E_k'=\dfrac{1}{2}m(2v)^2[/tex]
[tex]E_k'=4\times \dfrac{1}{2}mv^2[/tex]
[tex]E_k'=4\times E_k[/tex]
So, if the speed of an object doubles, its kinetic energy becomes four times. Hence, this is the required solution.
