Using the debroglie wavelength,
[tex] p = mv = \frac{h}{\lambda} [/tex]
where [tex]p[/tex] is the electron momentum, [tex]m[/tex] is the mass, [tex]v[/tex] is the velocity and [tex]h[/tex] is planck's constant. Substituting the wavelength as [tex]2.50nm[/tex], we have [tex]v = 290933 m/s[/tex]. Thus, the kinetic energy, is: [tex] \frac{1}{2}*9.11*10^{-31}* 290933^{2} =3.85*10^{-20}J [/tex]