Respuesta :
The answer is 165.3 cm³.
P1 * V1 / T1 = P2 * V2 / T2
The initial sample:
P1 = 84.6 kPa
V1 = 215 cm³
T1 = 23.5°C = 23.5 + 273 K = 296.5 K
At STP:
P2 = 101.3 kPa
V2 = ?
T2 = 273 K
Therefore:
84.6 * 215 / 296.5 = 101.3 * V2 / 273
61.34 = 101.3 * V2 / 273
V2 = 61.34 * 273 / 101.3
V2 = 165.3 cm³
P1 * V1 / T1 = P2 * V2 / T2
The initial sample:
P1 = 84.6 kPa
V1 = 215 cm³
T1 = 23.5°C = 23.5 + 273 K = 296.5 K
At STP:
P2 = 101.3 kPa
V2 = ?
T2 = 273 K
Therefore:
84.6 * 215 / 296.5 = 101.3 * V2 / 273
61.34 = 101.3 * V2 / 273
V2 = 61.34 * 273 / 101.3
V2 = 165.3 cm³
The term "volume" refers to the amount of three-dimensional space taken up by an item or a closed surface. It is denoted by V and its si unit is in cubic cm. The volume at STP will be 165.3 [tex]\rm{{cm}^3}[/tex].
What is volume?
The term "volume" refers to the amount of three-dimensional space taken up by an item or a closed surface. It is denoted by V and its si unit is in cubic cm.
According to the ideal gas equation at STP
[tex]PV_= nRT[/tex]
[tex]P_1 =[/tex]84.6 k pa
[tex]V_1[/tex]= 215 [tex]cm^3[/tex]
[tex]T_1= 273+23.5=296.5K[/tex]
At STP
[tex]P_2=[/tex]101.3 k pa
[tex]V_2[/tex]=?
[tex]T_2= 273[/tex] K
From ideal gas law on equating for 1 and STP conditions we get
[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]
[tex]\frac{84.6\times215}{296.5} =\frac{101.3\times V_2}{273}[/tex]
[tex]\rm{V_2}= 165.3 cm^{3}[/tex]
Hence the volume at STP will be 165.3 [tex]\rm{{cm}^3}[/tex].
To know more about the ideal gas equation refer to the link;
https://brainly.com/question/4147359