Answer:
11 units
Step-by-step explanation:
Hello, I can help you with this
Step one
define
to find the area of an irregular shape you can divide this are into others more common and known shapes like:square, triangle, circle, rectangle, in this case, let's divide the area into 2 shapes a square and a triangle,
let
the square
side=7
area= side*side
Area=7*7 = 49 square units
triangle
the base of the triangle would be= x-7 (it is necesary subtract 7 for base, those 7 units are counted in the square)
base=(x-7)
height= 7
Area=(b*h)/2
Area=((x-7)*7)/2
Area=(7x-49)/2
the total area is the area of the square plus the area of the triangle
[tex]49+\frac{7x-49}{2}=63\\[/tex]
Step 2
solve for x
[tex]49+\frac{7x-49}{2}=63\\\frac{7x-49}{2}=63-49\\\frac{7x-49}{2}=14\\7x-49=14*2\\7x-49=28\\\\7x=28+49\\7x=77\\x=\frac{77}{7}\\ x=11\\[/tex]
have a good day
