Respuesta :
Since we want either an e tile OR a y tile, then they are not simultaneous. Thus, we add up the probabilities to form our final probability.
The total number of possibilities is: 5 + 3 + 1 + 2 + 3 + 1 = 15, because there are 15 tiles to choose from.
Now, P(e tile) = 3/15 = 1/5
P(y tile) = 1/15
When we add them up, we get: P(e tile or y tile): 3/15 + 1/15 = 4/15
Thus, we have a 4/15 in choosing an E or a Y tile on the next draw.
The total number of possibilities is: 5 + 3 + 1 + 2 + 3 + 1 = 15, because there are 15 tiles to choose from.
Now, P(e tile) = 3/15 = 1/5
P(y tile) = 1/15
When we add them up, we get: P(e tile or y tile): 3/15 + 1/15 = 4/15
Thus, we have a 4/15 in choosing an E or a Y tile on the next draw.
