Respuesta :
x = $ 10 dvd's.....y = $ 12 dvd's
x + y = 200....x = 200 - y
10x + 12y = 2200
10(200 - y) + 12y = 2200
2000 - 10y + 12y = 2200
-10y + 12y = 2200 - 2000
2y = 200
y = 200/2
y = 100 ....so there were 100 $ 12 dvd's sold
x + y = 200....x = 200 - y
10x + 12y = 2200
10(200 - y) + 12y = 2200
2000 - 10y + 12y = 2200
-10y + 12y = 2200 - 2000
2y = 200
y = 200/2
y = 100 ....so there were 100 $ 12 dvd's sold
The number of $12 DVD movies that were sold by the movie store was calculated to be; 100
How to solve inequalities?
Let x represent the number of $10 movies and let y represent the number of $12 cost movie
We are told that number of both = 200 DVD movies. Thus;
x + y = 200 ..... (1)
Applying the cost of both gives;
10x + 12y = 2200 .... (2)
Solving both equations simultaneously gives;
x = 100 movies and y = 100 movies
Thus, the number of $12 DVD's sold is 100 DVD movies.
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