A store is having a sale on 200 dvd movies.some of the movies are being sold for $10 and some are being sold for $12.if the store made $2200 after selling all 200 dvds,how many $12 dvds were sold?

Respuesta :

x = $ 10 dvd's.....y = $ 12 dvd's

x + y = 200....x = 200 - y
10x + 12y = 2200

10(200 - y) + 12y = 2200
2000 - 10y + 12y = 2200
-10y + 12y = 2200 - 2000
2y = 200
y = 200/2
y = 100 ....so there were 100 $ 12 dvd's sold

The number of $12 DVD movies that were sold by the movie store was calculated to be; 100

How to solve inequalities?

Let x represent the number of $10 movies and let y represent the number of $12 cost movie

We are told that number of both = 200 DVD movies. Thus;

x + y = 200 ..... (1)

Applying the cost of both gives;

10x + 12y = 2200 .... (2)

Solving both equations simultaneously gives;

x = 100 movies and y = 100 movies

Thus, the number of $12 DVD's sold is 100 DVD movies.

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