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A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not replaced. Let event B be choosing a black ball first and event R be choosing a red ball second. What are the following probabilities?

Respuesta :

First answer: 8/12
Second answer: 4/11
Third answer: 8/33
fourth answer: 24 percent

The probability of choosing a black ball is [tex]\mathbf{= \dfrac{8}{12}}[/tex]

The probability of choosing a red ball  is [tex]\mathbf{=\dfrac{4}{12}}[/tex]

What is probability?

In mathematics, Probability is the likelihood of an event to occur or not. It is defined as the number of required outcomes divided by the total number of possible outcomes.

From the given parameters;

  • If B represents the event of choosing a black ball first;
  • and R represents the event of choosing a red ball second.

Then, the probability of B can be computed as:

[tex]\mathbf{=\dfrac{B}{B+R}}[/tex]

[tex]\mathbf{=\dfrac{8}{8+4}}[/tex]

[tex]\mathbf{=\dfrac{8}{12}}[/tex]

The probability of R can be computed as:

[tex]\mathbf{=\dfrac{4}{8+4}}[/tex]

[tex]\mathbf{=\dfrac{4}{12}}[/tex]

Learn more about probability here:

https://brainly.com/question/24756209