Dividing by [tex]2^x[/tex] gives:
[tex]\frac{2^y}{2^x} = 4 [/tex]
Using basic rules of exponents, we have:
[tex]2^{y-x} = 4 [/tex]
Taking the logarithm with base two gives:
[tex]y-x = 2[/tex]
Then, adding [tex]x-2[/tex] to both sides gives:
[tex]x=y-2[/tex]
Let me know if you have any further questions!
