Which of the following is not a way to represent the solution of the inequality
3(2x − 1) greater than or equal to 4(2x − 3) − 3?

x less than or equal to 6

6 greater than or equal to x A number line with a closed circle on 6 and shading to the left

A number line with a closed circle on 6 and shading to the right

[tex]3(2x-1)\geq 4(2x-3)-3[/tex]
[tex]6x-3\geq 8x-12-3[/tex]
[tex]6x-8x\geq -12-3+3[/tex]
[tex]-2x\geq -12[/tex]
[tex]x\leq 6[/tex]

1. x less than or equal to 6 - TRUE

2. 6 greater than or equal to x - TRUE

3. A number line with a closed circle on 6 and shading to the left - TRUE

4. A number line with a closed circle on 6 and shading to the right - FALSE

Answer Link

chisnau chisnau · Answer 2 · 2019-06-25T13:00:29+02:00

Answer:

D) A number line with a closed circle on 6 and shading to the right

Step-by-step explanation:

Which of the following is not a way to represent the solution of the inequality

?

3(2x- 1) greater than or equal to 4(2x-3)-3?

[tex]3(2x-1) \geq 4(2x-3)-3[/tex]

[tex]6x-3 \geq 8x-12-3[/tex]

[tex]6x-3 \geq 8x-15[/tex]

[tex]6x-8x \geq -15+ 3[/tex]

[tex]-2x \geq -12[/tex]

[tex]x\leq \frac{-12}{-2}[/tex]

[tex]x\leq 6[/tex]

So option D) A number line with a closed circle on 6 and shading to the right is incorrect. Rest all options are correct.