A group of 625 students has a mean age of 15.8 years with a standard deviation of 0.6 years. The ages are normally distributed. How many students are younger than 16.2 years? Express answer to the nearest student.

Respuesta :

16.2-15.8/0.6=0.6667. Use normalcdf() to find the percentage from -999 to 0.6777 which is 0.7476*625=467

Normal Probability Theorem :

The Z-score of the standard normal distribution is used under the normal probability to calculate the number of younger males. The Z-score is a measure of the standard deviation of the distribution from the mean value of the distribution.

Given: A group of 625 students has a mean age of 15.8 years with a standard deviation of 0.6 years. The ages are normally distributed.

How to find how many students are younger than 16.2 years?

Mean = 15.8

SD = 0.6

Z score = ( Value  - Mean ) .SD

Value  = 16.2 years

=> Z score = ( 16.2 - 15.8)/0.6  =  2/3 = 0.6667

from z score table :

0.7464   portion of students are   younger than 16.2 years

=> 625 * 0.7464 = 466.5

= 466

Therefore, 466 Students are younger than 16.2 years.

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