Answer:
[tex]\text{The value of }(b^2-4ac)\thinspace is\thinspace 169[/tex]
Step-by-step explanation:
Given the equation [tex] 5x^2 + 7x = 6[/tex]
we have to find the value of [tex]b^2-4ac[/tex]
Equation: [tex]5x^2+7x-6=0[/tex]
Comparing above with general quadratic equation [tex]ax^2+bx+c=0[/tex]
we get, a=5, b=7 and c=-6
[tex]b^2-4ac=(7)^2-4(5)(-6)=49+120=169[/tex]
Hence,
[tex]\text{The value of }(b^2-4ac)\thinspace is\thinspace 169[/tex]
