Answer:
The value of the discriminant is 12.
Step-by-step explanation:
We are given the quadratic equation is [tex]2x^2-2x-1=0[/tex].
Now, we know,
The discriminant for the quadratic equation [tex]ax^2+bx+c=0[/tex] is given by [tex]D=b^2-4ac[/tex].
On comparing the equations, we have,
a= 2, b= -2 and c= -1
So, the discriminant is given by,
[tex]D=(-2)^2-4\times 2\times (-1)[/tex]
i.e. [tex]D=4+8[/tex]
i.e. D= 12
Hence, the value of the discriminant is 12.
