Answer:
B. L=15 units
Step-by-step explanation:
We have four points:
P(-2,1)
Q(6,1)
R(6,-3)
S(9,-3)
If you have two points [tex]A=(x_{1},y_{1}) , B=(x_{2},y_{2})[/tex] the distance between those points is the length of the segment that separates them. And the formula of that distance is:
[tex]d(A,B)=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Then we have to calculate:
1. The distance between P and Q:
[tex]d(P,Q)=\sqrt{(6-(-2))^2+(1-1)^2}=\sqrt{8^2}=8[/tex]
2. The distance between Q and R:
[tex]d(Q,R)=\sqrt{(6-6)^2+(-3-1)^2}=\sqrt{(-4)^2}=4[/tex]
3. The distance between R and S:
[tex]d(R,S)=\sqrt{(9-6)^2+(-3-(-3))^2}=\sqrt{(3)^2}=3[/tex]
Then the total length of the biking trail is:
[tex]L=d(P,Q)+d(Q,R)+d(R,S)\\L=8+4+3\\L=15 units[/tex]
The answer is:
B. L=15 units
