Respuesta :
since quadratic coefient is 1 (term in front of x^2)
take 1/2 of linear cofient (12) and square it
12/2=6, 6^2=36
add that to both sides
x^2+12x+36=-11+36
factor perfect square
(x+6)^2=25
sqrt both sides and take positiv and negative roots
x+6=+/-5
minus 6 both sides
x=-6+/-5
x=-6+5 or x=-6-5
x=-1 or -11
answer is {-11,-1}
take 1/2 of linear cofient (12) and square it
12/2=6, 6^2=36
add that to both sides
x^2+12x+36=-11+36
factor perfect square
(x+6)^2=25
sqrt both sides and take positiv and negative roots
x+6=+/-5
minus 6 both sides
x=-6+/-5
x=-6+5 or x=-6-5
x=-1 or -11
answer is {-11,-1}
The solution which is a set of the equation is; {–11, –1}
Completing the square
The given equation is;
- x² + 12x = –11
Therefore, by completing the square method; we have;
- (x+ 6)² -36 = -11
- (x+6)² = 25
- x+6 = ±5
Hence, x = -11 or x = -1
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