Solve x2 + 12x = –11 by completing the square. Which is the solution set of the equation? {–11, –1} {–11, 1} {11, –1} {11, 1} , PLEASE HURRY !! :( THANK YOU!

Respuesta :

since quadratic coefient is 1 (term in front of x^2)
take 1/2 of linear cofient (12) and square it
12/2=6, 6^2=36
add that to both sides
x^2+12x+36=-11+36
factor perfect square
(x+6)^2=25
sqrt both sides and take positiv and negative roots
x+6=+/-5
minus 6 both sides
x=-6+/-5
x=-6+5 or x=-6-5
x=-1 or -11

answer is {-11,-1}

The solution which is a set of the equation is; {–11, –1}

Completing the square

The given equation is;

  • x² + 12x = –11

Therefore, by completing the square method; we have;

  • (x+ 6)² -36 = -11

  • (x+6)² = 25

  • x+6 = ±5

Hence, x = -11 or x = -1

Read more on completing the square method;

https://brainly.com/question/24860429

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