Answer: The required length of a side of the square is (x - 6) units.
Step-by-step explanation: Given that the area of a square is as follows :
[tex]A(x)=x^2-12x+36~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
We are to find the length of a side of the square.
We know that
all the sides of a square have equal length l, and its area is given by
[tex]A=l^2.[/tex]
From expression (i), we have
[tex]A(x)\\\\=x^2-12x+36\\\\=x^2-2\times x\times 6+6^2\\\\=(x-6)^2.[/tex]
Therefore, the required length of a side of the square is (x - 6) units.
