Seudónimo
Seudónimo
11-04-2017
Mathematics
contestada
help with math question please
thanks so much
Respuesta :
Аноним
Аноним
11-04-2017
[tex] \frac{-b(+/-) \sqrt{b^{2} + 4ac}}{2a} [/tex]
where ax^2+bx+c=0
a=1
b=-2
c=-4
Just plug in.
x=1+√5
x=1-√
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Аноним
Аноним
11-04-2017
[tex]x=1 \sqrt{5} [/tex]
[tex]x=3.23606797,-1.23606797[/tex]
Hope my answer helped!
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