RJMotoRider
contestada

A box shaped like a rectangular prism has a height of 17 in and a volume of 2,720 in3 the lenght is 4 inches greter than twice the width. what is the width of the box?

Respuesta :

so.. if the width is  say  "w", twice the width will then be 2*w or 2w
and 4 greater than that, => 2w + 4

thus   [tex]\bf \qquad \qquad \textit{volume of a rectangular prism}\\\\ V=l\cdot w\cdot h\qquad \begin{cases} l=length\\ w=width\\ h=height\\ -------\\ h=17\\ l=2w+4\\ V=2,720 \end{cases}\implies 2720=(2w+4)(w)(17)[/tex]

solve for "w"

Ohorses2001
The height is 17, the length is 2w+4 and the width = w.
So you need to know V=2720^3= (17)(2w+4)(w)
Now you just combine and solve for W
hope this helps