He isotope 62(over28ni has the largest binding energy per nucleon of any isotope. calculate this value from the atomic mass of nickel-62 (61.928345 amu.
The atomic mass of the isotope Ni ( 62 over 28 ) = 61.928345 amu. Mass of the electrons: 28 · 5.4584 · 10^(-4 ) amu = 0.0152838 amu ( g/mol ) Mass of the nuclei: 61.928345 amu - 0.0152838 amu = 61.913062 amu (g/mol) The mass difference between a nucleus and its constituent nucleons is called the mass defect. For Ni ( 62 over 28 ): Mass of the protons: 28 · 1.00728 amu = 28.20384 amu Mass of the neutrons: 34 · 1.00866 amu = 34.299444 amu In total : 62.49828 amu The mass defect = 62.49828 - 61.913062 = 0.585218 amu Nucleus binding energy: E = Δm · c² ( the Einstein relationship ) E = 0.585218 · ( 2.9979 · 10^8 m/s )² · 1 / (6.022 · 10^23) · 1 kg / 1000 g = = 0.585218 · 8.9874044 · 10 ^16 : (6.022 · 10^23) · 0.001 = = ( 5.2595908 : 6.022 ) · 0.001 · 10^(-7 ) = = 0.0008733 · 10^(-7) J = 8.733 · 10^(-11) J The nucleus binding energy per nucleon: 8.733 · 10^(-11) J : 62 = 0.14085 · 10 ^(-11) = = 1.4085 · 10^(-12) J per nucleon.
