Answer:
f(t) = 3900·1.035^t
Step-by-step explanation:
You want an exponential function that represents the population of deer t years after 2005, if it was 3900 in 2005, growing at 3.5% per year.
The exponential function will have the form ...
f(t) = a·b^t
where 'a' is the initial value, and 'b' is the growth factor. The growth factor is 1 more than the growth rate of 3.5%.
f(t) = 3900·(1 + .035)^t . . . . . equation with given numbers filled in
f(t) = 3900·1.035^t . . . . . . . exponential function for deer population
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