Answer:
To determine how many grams of crystals will be formed when a saturated potassium nitrate solution is cooled from 60°C to 30°C, we can use the solubility curve for potassium nitrate.
First, we need to find the solubility of potassium nitrate at both 60°C and 30°C by reading the solubility curve. Let's say the solubility of potassium nitrate at 60°C is approximately 120g KNO3/100g H2O, and the solubility at 30°C is approximately 80g KNO3/100g H2O.
Next, we need to calculate the amount of KNO3 that was initially dissolved at 60°C and the amount of KNO3 that can still remain in solution at 30°C. If we assume that we dissolved 100g of KNO3 into 100g of water at 60°C to make a saturated solution, then the amount of KNO3 that was initially dissolved is 120g.
At 30°C, the solubility of KNO3 is 80g/100g H2O. So, the maximum amount of KNO3 that can remain dissolved in 100g of water at 30°C is 80g.
Subtracting these two values, we get the amount of KNO3 that will crystallize out of the solution as it cools: 120g - 80g = 40g of KNO3
Therefore, approximately 40 grams of KNO3 crystals will be formed when a saturated solution of potassium nitrate is cooled from 60°C to 30°C.
Explanation:
