PART 2:  SHOW YOUR STEPS AND WORK

5) 4.2(1.2b) - (-0.9b) /2 = 5.94

6) 7/3(c+3) = 1/3-c

7) 1 1/6g +3 3/2 -2 1/3 -5 =0

8) 9.1= 2.8(4h-1 ) /4

Respuesta :

I don't know 5 and 7 it's to complicated for me plus I haven't learned how do those kind

6)7/3 (c+3)=1/3-c
7/3c+7=1/3-c
3×7/3c+3×7=3×1/3-3c
7c+3c=1-21
10c=-20
c=-2
zimmah
[tex]4.2(1.2b)- \frac{-0.9b}{2} =5.94 [/tex]
[tex]5.04b--0.45b =5.94[/tex]
[tex]5.04b+0.45b =5.94[/tex]
[tex]5.49b=5.94[/tex]
[tex]b = \frac{5.94}{5.49} = 1.08197 (approximately)[/tex]

[tex]7/3(c+3) = 1/3-c[/tex]
[tex] \frac{7c}{3} + 7 = \frac{1}{3} - c[/tex]
[tex]7c+21 = 1 - 3c[/tex]
[tex]10c+21 = 1 [/tex]
[tex]10c = -20 [/tex]
[tex]c=-2[/tex]

[tex] \frac{11g}{6} + \frac{9}{2} - \frac{2}{3} -5 =0[/tex] (I interpret 3 3/2 as 3 times 3/2, although this unconventional writing method could be interpret in multiple ways and should be avoided)
[tex] \frac{11g}{6} + \frac{27}{6} - \frac{4}{6} - \frac{30}{6} =0[/tex]
[tex]11g+27-4-30=0[/tex]
[tex]11g-7=0[/tex]
[tex]11g=7[/tex]
[tex]g = \frac{7}{11} [/tex]

[tex]9.1= \frac{2.8(4h-1 )}{4} [/tex]
[tex]36.4= 11.2h-2.8[/tex]
[tex]39.2= 11.2h[/tex]
[tex]h= \frac{39.2}{11.2} =3.5[/tex]