You own a high speed digital camera that can take a picture every 0.5 seconds. You decide to take a picture every 0.5 seconds of your physics teacher as she drops a watermelon off the top of the school. After you develop and analyze the pictures, you realize that the distance the watermelon falls from the teacher in each new picture is

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AL2006
The distance it falls in each picture is greater than in the last picture.

Answer:

here distance covered by drop in each picture is increasing

Explanation:

here as we know that drop is falling from certain height and we started to took the picture after every 0.5 seconds of time

now from the beginning it will fall by distance

[tex]d = \frac{1}{2}gt^2[/tex]

here we have

[tex]d = \frac{1}{2}(9.8)(0.5^2) = 1.225 m[/tex]

now distance covered in next picture will be given as

[tex]d = \frac{1]{2}(9.8)(1^2) = 4.9 m[/tex]

then in next 5 second interval the distance will be

[tex]d = \frac{1}{2}(9.8)(1.5^2) = 11.025 m[/tex]

so here the distance is continuously increasing with time in each interval of 0.5 s