Respuesta :
The first two ionization energy of nickel are expressed as:
Ni(g) = Ni^+(g) + e^- Ni^+(g) = Ni^2+(g) + e^-
IOnization energy os the energy that is neccessary in order to remove one mole of electrons from an atom.
Hope this helps.
Ni(g) = Ni^+(g) + e^- Ni^+(g) = Ni^2+(g) + e^-
IOnization energy os the energy that is neccessary in order to remove one mole of electrons from an atom.
Hope this helps.
We have that from the Question "The first two ionization energies of nickel." it can be said that we have that these are first two first two ionization energies
- [tex]Ni _g = Ni^+g + e^-[/tex]
- [tex]Ni^+g = Ni^2+g + e^-[/tex]
From the Question we are told
The first two ionization energies of nickel.
Generally
Ionization energy energy is the energy that is required by an atom to remove one electron from its valent shell .
Therefore
The first two ionization energies of nickel.
- [tex]Ni _g = Ni^+g + e^-[/tex]
- [tex]Ni^+g = Ni^2+g + e^-[/tex]
For more information on this visit
https://brainly.com/question/19007362?referrer=searchResults