Jon is launching rockets in an open field. The path of the rocket can be modeled by the quadratic function h(t) = -16t^2 + 96t, where h(t) is the height in feet any time t in seconds. After how many seconds will the rocket reach a height of 80 feet for the second time?
to solve the problem, substitute 80 feet to value of h(t). so given that h(t) = -16t^2 + 96t
so h(t) = -16t^2 + 96t = 80 -16t^2 + 96t - 80 = 0 divide the whole equation with -16 ( -16t^2 + 96t - 80 = 0) 1/-16 t^2 - 6t + 5 = 0 factor the quadratic equation ( t - 5 ) ( t - 1 ) = 0 t = 5 t = 1 so the answer would be 5 s, because it the rocket will reach the 80 ft for the first time at 1 s
