Respuesta :
-7-2=-9, -16--7=-9 so there is a common difference, -9, so we know that this is an arithmetic sequence.
The sum of an arithmetic sequence is just the average of the first and last terms time the number of terms...
a(n)=a+d(n-1), in this case a(9)=2-9(8)=-70
So the sum is (2-70)(9/2)=-306
The sum of an arithmetic sequence is just the average of the first and last terms time the number of terms...
a(n)=a+d(n-1), in this case a(9)=2-9(8)=-70
So the sum is (2-70)(9/2)=-306
Answer:
(-306)
Step-by-step explanation:
We have to find the sum of the first 9 terms of the sequence
Sequence is 2, -7, -16, -25 ....
As we can see in this sequence there is a common difference of T₂ - T₁
= -7 -2 = (-9)
Formula to calculate the sum of n terms of an arithmetic sequence is [tex]s_{n}=\frac{n}{2}[2a+(n-1)d][/tex]
Where a = first term = 2
d = common difference = (-9)
and n = number of terms = 9
[tex]s_{n}=\frac{9}{2}[/tex] [ 2× 2 + (9-1) (-9) ]
= [tex]\frac{9}{2}[/tex] [4-72]
= [tex]\frac{9}{2}[/tex] [-68]
= 9 (-34)
= (-306)