Respuesta :
A=p(1-0.08/12)^12t
A=p(1-0.08/52)^52t
A=p(1-0.08/360)^360t
0.08÷12=0.0067
0.08÷52=0.0015
0.08÷360=0.00022
A=p(1-0.08/52)^52t
A=p(1-0.08/360)^360t
0.08÷12=0.0067
0.08÷52=0.0015
0.08÷360=0.00022
Answer:
Since, the exponential decay function that models the present value,
[tex]f(x)=a(1-r)^x[/tex]
Where, a shows the initial value,
r shows rate of decay per period,
x is the number of periods,
Given,
Annual rate = 8 % = 0.08
1. 1 year = 12 months
So, monthly rate, r = [tex]\frac{0.08}{12}[/tex]
Number of periods in x years, t = 12x
Thus, the function would be,
[tex]f(x)=a(1-\frac{0.08}{12})^{12x}[/tex]
2. 1 year = 52 weeks
So, weekly rate, r = [tex]\frac{0.008}{52}=\frac{1}{6500}[/tex]
Number of periods in x years, t = 52x
Thus, the function would be,
[tex]f(x)=a(1-\frac{0.08}{52})^{52x}[/tex]
3. 1 year = 365 days
So, daily rate, r = [tex]\frac{0.008}{365}=\frac{1}{45625}[/tex]
Number of periods in x years, t = 365x
Thus, the function would be,
[tex]f(x)=a(1-\frac{0.08}{365})^{365x}[/tex]
4. Since, with increasing time the value of car will decrease,
Hence, there is an inverse relation between the amount of decrease and the time interval measured.