Answer:
Area of figure is 532 m²
Step-by-step explanation:
Consider the figure, It consist of a square ABCD , and two right triangles CDE and DEF.
We have to find the area of the figure
Area of figure = area of square ABCD + area of two right triangles CDE and DEF.
We find the areas separately and then add them,
First area of square ABCD,
Area of square = side × side
Given the side of square = 18 m
Area of square ABCD = 18 × 18 = 324 m²
Area of right angled triangle = [tex]\frac{1}{2} \times \text{base}} \times \text{height}[/tex]
For ΔCDE , base = 18 m and height is 16 m
Area of right angled triangle CDE = [tex]\frac{1}{2} \times 18 \times 16[/tex]
Area of right angled triangle CDE = 144 m².
Similarly, For ΔEDF , base = 8 m and height is 16 m
Area of right angled triangle EDF = [tex]\frac{1}{2} \times 8 \times 16[/tex]
Area of right angled triangle EDF = 64 m².
Thus, Area of figure is 324 + 144 + 64 = 532 m²
