Answer:
I think the answer is [tex]c=F(d^2)/(m_1m_2)[/tex]
Step-by-step explanation:
REMEMBER: The formula for joint variation is:
[tex]c=y/xz[/tex] OR [tex]y=cxz[/tex].
Substitute:
[tex]F=Km_1m_2/d^2[/tex]
then change to:
k= constant, they want you to use "c" instead:
[tex]c=F(d^2)/(m_1m_2)[/tex]
Hope this helps!
The expression of force of attraction F will be [tex]F=c\dfrac{M_1M_2}{d^2}[/tex].
Given information:
The force F of attraction between two bodies varies jointly as the weights of the two bodies and inversely as the square of the distance between them.
[tex]M_1[/tex] and [tex]M_2[/tex] are the weights of the two bodies.
Let d be the distance between the two bodies.
The force follows inverse square law.
The expression of force can be written as,
[tex]F\propto \dfrac{M_1M_2}{d^2}\\F=c\dfrac{M_1M_2}{d^2}[/tex]
where c is the proportionality constant.
Therefore, the expression of force of attraction F will be [tex]F=c\dfrac{M_1M_2}{d^2}[/tex].
For more details, refer to the link:
https://brainly.com/question/9510464
