Respuesta :

using distance formula =√(5-3)sq+(1-4)sq
=
√4+9
=√13

Answer:

3.6 units

Step-by-step explanation:

Given: The two points that are P(5,1) and Q(3,4).

To find: The distance between these two points.

Solution: It is given that there are two points that are P(5,1) and Q(3,4).

The distance between these two points can be found out as using the distance formula that is:

[tex]PQ=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2 }[/tex]

[tex]PQ=\sqrt{(4-1)^2+(3-5)^2}[/tex]

[tex]PQ=\sqrt{(3)^2+(-2)^2}[/tex]

[tex]PQ=\sqrt{9+4}[/tex]

[tex]PQ=\sqrt{13}[/tex]

[tex]PQ=3.6 units[/tex]

Thus, the distance between the given two points is 3.6 units.