We can use the ideal gas equation which is expressed as PV = nRT. At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:
T1/P1 = T2/P2
P2 = T2 x P1 / T1
P2 = 393.15 K x 1.04 atm / 478.15 K
P2 = 0.86 atm
Answer:
1.30 atm (rounded)
Explanation:
P1= 1.07 atm
P2= ?
T1= 122 Celsius (+273 to convert to Kelvin)= 395 K
T2= 205 Celsius (+273 to convert to Kelvin)= 478 K
[tex]\frac{P1}{T1} = \frac{P2}{T2}[/tex]
[tex]\frac{1.07 atm}{395 K} =\frac{P2}{478 K}[/tex]
[tex]P2=\frac{(1.07 atm) (478 K)}{395 K}[/tex]
[tex]=\frac{511.46}{395} = 1.29483544304[/tex]
= 1.30 atm
