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the answer
Andrew swims 7/11 of a lap in 1/3 of a minute means
v=7/11 : 1/3 =3 x 7 / 11= 21 /11
Andrew swims 7/11 of a lap in 1/3 of a minute means
v=7/11 : 1/3 =3 x 7 / 11= 21 /11
Andrew's unit rate of swimming is [tex]1\frac{10}{11} \ laps \ per \ minute[/tex]. The correct option is C:1 10/11
From the question,
Andrew swims 7/11 of a lap in 1/3 of a minute.
To determine Andrew's unit rate for swimming in laps per minute, we will divide the distance Andrew covers by the time spent to cover that distance.
Using the formula,
[tex]Rate =\frac{Distance}{Time}[/tex]
From the question
Distance = 7/11 lap
and
Time = 1/3 minute
Then,
[tex]Rate = \frac{7}{11} \div \frac{1}{3}[/tex]
[tex]Rate = \frac{7}{11} \times \frac{3}{1}[/tex]
[tex]Rate = \frac{21}{11}[/tex]
∴ [tex]Rate = 1\frac{10}{11} \ laps \ per \ minute[/tex]
Hence, Andrew's unit rate of swimming is [tex]1\frac{10}{11} \ laps \ per \ minute[/tex]. The correct option is C:1 10/11
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