The value for which test score is below 95% percent for the given mean and standard deviation on a college placement is equal to 696.
As given in the question,
Given : 95% of the test takers score are below z.
z-score is given by,
z=(x-μ)/σ
Mean of the score 'μ' = 500
Standard deviation of the score ' σ' = 100
Z = 95%
= 0.95
P(z<Z) = 1-0.95
= 0.05
The value of z which corresponds to 0.05 in the table is equal to 1.96.
Substitute all the values we get,
z=(x-μ)/σ
⇒1.96 = ( x - 500 ) / 100
Multiply by 100 both the sides we get,
⇒ 196 = ( x - 500 )
⇒ x = 696
Therefore, the value for which test score is below 95% percent for the given mean and standard deviation is equal to 696.
learn more about standard deviation here
brainly.com/question/23907081
#SPJ4
