Using the equation of the plane and the provided point (1,2,3) with the unit values perpendicular to the plane .The answer is [tex]\frac{x-1}{3.14} + \frac{y-2}{3.14} + \frac{z-3}{3.14} = 1[/tex]
A plane is a doubly ruled surface in two dimensions that is spanned by two linearly independent vectors. A hyperplane is a generalization of the plane to higher dimensions. The dihedral angle is the angle formed by two intersecting planes.
A normal in geometry is a piece of geometry that is perpendicular to another piece of geometry, such as a line, ray, or vector. For instance, the (infinite) line perpendicular to the tangent line to the curve at the point is the normal line to a plane curve at the point.
x1=1
y1=2
z1=3
[tex]\frac{x-x1}{\sqrt{x1^{2}+y1^{2}+z1^{2}}} + \frac{y-2}{\sqrt{x1^{2}+y1^{2}+z1^{2}}} + \frac{z-3}{\sqrt{x1^{2}+y1^{2}+z1^{2}}} = 1[/tex]
[tex]\frac{x-1}{3.14} + \frac{y-2}{3.14} + \frac{z-3}{3.14} = 1[/tex]
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